# Line slope calculator x-3y=-11

**Straight line given by points A[1; 4] and B[4; 5]**

## Calculation:

**Slope-intercept form of line:**y = 0.3333x+3.6667

**Canonical form of the line equation:**x-3y+11 = 0

**Parametric form of the line equation:**

x = 3t+1

y = t+4 ; t ∈ R

**Slope:**m = 0.3333

**Slope angle of line: φ =**18°26'6″ = 0.3218 rad

**X intercept:**x

_{0}= -11

**Y intercept:**y

_{0}= q = 3.6667

**Distance line from the origin:**d

_{0}= 3.4785

**The length of the segment AB: |AB| =**3.1623

**Vector: AB =**(3; 1)

**Normal vector: n =**(1; -3)

**Midpoint of the segment AB: M =**[2.5; 4.5]

**Perpendicular Bisector equation:**3x+y-12 = 0

**Vector OA = (1; 4) ; |OA| = 4.1231**

**Vector OB = (4; 5) ; |OB| = 6.4031**

**Scalar product OA .OB = 24**

**Angle ∠ AOB = 24°37'25″ = 0.4298 rad**